The RMS value of an ideal bipolar square wave that alternates between +Vdc and -Vdc is?

  • AVdc/2
  • BVdc/sqrt(2)
  • CVdc
  • Dsqrt(2)Vdc
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Correct Answer: C. Vdc
Explanation: The magnitude is Vdc throughout the cycle, so RMS=sqrt(mean(Vdc²))=Vdc.
Reference: Standard power electronics: inverter numericals
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