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MCQ Practice Question
Electronic Devices & CircuitsBJT

In the BJT active region, the common-base current gain alpha is related to common-emitter beta by?

  • Aalpha = beta/(beta+1)
  • Balpha = beta+1
  • Calpha = 1/beta
  • Dalpha = beta-1
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Correct Answer: A. alpha = beta/(beta+1)
Explanation: Since IE=IC+IB and beta=IC/IB, alpha=IC/IE=beta/(beta+1).
Reference: Standard transistor electronics: alpha-beta relation
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