MCQ Practice Question
A series RLC circuit has R=10 ohm, L=0.1 H and C=100 microfarad. Its quality factor at resonance is approximately?
Correct Answer: B. 3.16
Explanation: For a series RLC circuit, Q=omega0 L/R=sqrt(L/C)/R. sqrt(0.1/100e-6)=sqrt(1000)=31.62, so Q≈3.16.
Reference: Standard network theory: series resonance Q
