For a BJT biased at IC = 1 mA at room temperature, the small-signal transconductance gm is approximately, using VT = 25 mV?

  • A0.004 S
  • B0.04 S
  • C0.4 S
  • D40 S
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Correct Answer: B. 0.04 S
Explanation: For a BJT, gm = IC/VT. Thus gm = 1 mA / 25 mV = 0.04 S = 40 mS.
Reference: Standard analog electronics: BJT small-signal transconductance