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Network TheoryLaplace Transform

The inverse Laplace transform of 1/[(s+2)(s+3)] is?

  • Ae^(-2t)+e^(-3t)
  • Be^(-2t)-e^(-3t)
  • C2e^(-2t)-3e^(-3t)
  • De^(-5t)
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Correct Answer: B. e^(-2t)-e^(-3t)
Explanation: Partial fractions give 1/(s+2)-1/(s+3), hence f(t)=e^(-2t)-e^(-3t) for t>=0.
Reference: Standard network theory: partial fractions numerical
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