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Communication SystemsAmplitude Modulation

For the same AM transmitter with Pc=400 W and m=0.6, the total transmitted power is?

  • A400 W
  • B436 W
  • C472 W
  • D544 W
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Correct Answer: C. 472 W
Explanation: Pt=Pc(1+m^2/2)=400(1+0.18)=472 W.
Reference: Standard communication systems: AM total power numerical
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