At T=290 K and bandwidth B=1 MHz, thermal-noise power kTB is approximately?

  • A4.0×10^-21 W
  • B4.0×10^-15 W
  • C2.9×10^-7 W
  • D1.38×10^-23 W
Report an error
Correct Answer: B. 4.0×10^-15 W
Explanation: N=kTB≈1.38×10^-23×290×10^6≈4.0×10^-15 W.
Reference: Standard communication systems: thermal noise numerical