If the transistor in the previous type of fixed-bias circuit has beta = 100 and IB = 20 microampere while remaining in active region, IC is approximately?

  • A0.2 mA
  • B2 mA
  • C20 mA
  • D200 mA
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Correct Answer: B. 2 mA
Explanation: IC = beta IB = 100 × 20 microampere = 2 mA.
Reference: Standard transistor bias calculation