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Signals & SystemsDTFT

For a real-valued sequence x[n], its DTFT has conjugate symmetry given by?

  • AX(e^(-jω))=X*(e^(jω))
  • BX(e^(-jω))=-X*(e^(jω)) always
  • CX(e^(jω))=0
  • DX(e^(jω)) is always purely real
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Correct Answer: A. X(e^(-jω))=X*(e^(jω))
Explanation: A real time-domain sequence has a conjugate-symmetric DTFT: X(e^(-jω))=X*(e^(jω)).
Reference: Standard signals and systems: dtft
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