MCQ Practice Question

The centroid of root-locus asymptotes is located at?

  • A(sum of poles - sum of zeros)/(n-m)
  • B(sum of poles + sum of zeros)/(n+m)
  • CProduct of poles divided by product of zeros
  • DOrigin in every system
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Correct Answer: A. (sum of poles - sum of zeros)/(n-m)
Explanation: For n>m, the asymptote centroid is σa=(Σpoles-Σzeros)/(n-m).
Reference: Standard control systems: root locus
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