A 0.5 m conductor carries 4 A perpendicular to a uniform 0.2 T magnetic field. The force magnitude is?

  • A0.04 N
  • B0.1 N
  • C0.4 N
  • D4 N
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Correct Answer: C. 0.4 N
Explanation: F=BIL sin90°=0.2×4×0.5=0.4 N.
Reference: Standard electromagnetic theory: magnetic force