A BJT has VCC = 10 V, RC = 2 kOhm and collector current IC = 2 mA. Neglecting emitter resistance, VCE is approximately?

  • A2 V
  • B4 V
  • C6 V
  • D10 V
Report an error
Correct Answer: C. 6 V
Explanation: The drop across RC is IC RC = 2 mA × 2 kOhm = 4 V. Thus VCE ≈ 10 - 4 = 6 V.
Reference: Standard transistor bias: collector circuit calculation