A device emits light of wavelength 620 nm. Using hc approximately 1240 eV·nm, the photon energy is closest to?

  • A0.5 eV
  • B1 eV
  • C2 eV
  • D4 eV
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Correct Answer: C. 2 eV
Explanation: E≈1240/620=2 eV.
Reference: Standard optoelectronics: photon energy calculation