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Network TheorySource Transformation

A Norton source of 5 A in parallel with 8 ohm is transformed to a Thevenin source of?

  • A5 V in series with 8 ohm
  • B13 V in series with 8 ohm
  • C40 V in series with 8 ohm
  • D40 V in series with 1.6 ohm
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Correct Answer: C. 40 V in series with 8 ohm
Explanation: Vth=IN RN=5×8=40 V and Rth=RN=8 ohm.
Reference: Standard network theory: Norton to Thevenin numerical
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