MCQ Practice Question
A series RLC circuit has R = 10 ohm and L = 0.1 H. Its bandwidth in rad/s is R/L, equal to?
Correct Answer: B. 100 rad/s
Explanation: For a series RLC circuit, bandwidth in angular frequency is Δomega = R/L = 10/0.1 = 100 rad/s.
Reference: Standard network theory: resonance
