MCQ Practice Question
A transistor dissipates 2 W. If the total junction-to-ambient thermal resistance is 25 degrees C/W and ambient temperature is 30 degrees C, the estimated junction temperature is?
Correct Answer: C. 80 degrees C
Explanation: Temperature rise = P times thermal resistance = 2×25 = 50 degrees C. Junction temperature = 30+50 = 80 degrees C.
Reference: Standard analog electronics: power amplifiers
