An AM wave has maximum envelope voltage 15 V and minimum envelope voltage 5 V. Its modulation index is?

  • A0.25
  • B0.5
  • C0.667
  • D2
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Correct Answer: B. 0.5
Explanation: m=(Vmax-Vmin)/(Vmax+Vmin)=(15-5)/(15+5)=10/20=0.5.
Reference: Standard communication systems: modulation index from envelope