An n-channel JFET has IDSS = 8 mA and VP = -4 V. Using Shockley’s equation, the drain current at VGS = -2 V is?

  • A1 mA
  • B2 mA
  • C4 mA
  • D8 mA
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Correct Answer: B. 2 mA
Explanation: ID = IDSS(1 - VGS/VP)^2 = 8(1 - (-2/-4))^2 = 8(0.5)^2 = 2 mA.
Reference: Standard electronics: JFET Shockley-equation calculation