MCQ Practice Question
For a BJT biased at IC = 1 mA at room temperature, the small-signal transconductance gm is approximately, using VT = 25 mV?
Correct Answer: B. 0.04 S
Explanation: For a BJT, gm = IC/VT. Thus gm = 1 mA / 25 mV = 0.04 S = 40 mS.
Reference: Standard analog electronics: BJT small-signal transconductance
