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MCQ Practice Question

Electronic Devices & Circuits BJT Biasing

For a fixed-bias NPN transistor with VCC = 10 V, RB = 470 kOhm, emitter grounded and VBE = 0.7 V, the base current is closest to?

A2 microampere
B20 microampere
C200 microampere
D2 mA

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Correct Answer: B. 20 microampere

Explanation: IB = (VCC - VBE)/RB = 9.3 V / 470 kOhm ≈ 19.8 microampere, about 20 microampere.

Reference: Standard transistor bias calculation

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