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Control SystemsTime Response

For a standard underdamped second-order system, percentage overshoot is given by?

  • A100e^[-πζ/√(1-ζ²)]
  • B100ζωn
  • C100/(1+ζ)
  • D100e^(-ωn)
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Correct Answer: A. 100e^[-πζ/√(1-ζ²)]
Explanation: The standard step-response percentage overshoot is PO=100 exp[-πζ/√(1-ζ²)] for 0<ζ<1.
Reference: Standard control systems: time response
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