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Communication SystemsMultiplexing

If 10 TDM channels each generate 8 kbps and overhead is neglected, the minimum aggregate data rate is?

  • A8 kbps
  • B80 kbps
  • C800 kbps
  • D1 Mbps
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Correct Answer: B. 80 kbps
Explanation: The aggregate rate is the sum of channel rates: 10×8 kbps = 80 kbps.
Reference: Standard communication systems: multiplexing
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