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Electronic Devices & CircuitsSemiconductor Fundamentals

If the electron concentration in an n-type semiconductor is 10^16 cm^-3 and ni = 10^10 cm^-3, the equilibrium hole concentration is approximately?

  • A10^2 cm^-3
  • B10^4 cm^-3
  • C10^6 cm^-3
  • D10^10 cm^-3
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Correct Answer: B. 10^4 cm^-3
Explanation: Using np=ni², p=(10^10)²/10^16=10^4 cm^-3.
Reference: Standard semiconductor electronics: minority carrier concentration
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