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MCQ Practice Question
Measurements & InstrumentationThree-Phase Measurement

In the two-wattmeter method for a balanced three-phase load, total real power equals?

  • AW1+W2
  • BW1-W2 always
  • CW1×W2
  • D(W1+W2)/2
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Correct Answer: A. W1+W2
Explanation: The algebraic sum of the two wattmeter readings gives total three-phase real power.
Reference: Standard measurements and instrumentation: three-phase measurement
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