MCQ Practice Question
Using FSPL(dB)=32.44+20log10(fMHz)+20log10(dkm), the free-space path loss at 100 MHz over 10 km is approximately?
Correct Answer: C. 92.4 dB
Explanation: FSPL=32.44+40+20=92.44 dB.
Reference: Standard antenna and wave propagation: link budget
