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8086 Segmentation MCQs

Practice 8086 Segmentation MCQs with four options, answers and explanations for focused Electronics & Telecommunication Engineering revision.

Question 1
Microprocessors & Microcontrollers8086 Segmentation

The 8086 physical address is calculated from segment and offset as?

  • ASegment × 16 + offset
  • BSegment + offset only
  • CSegment × 256 + offset
  • DOffset × 16 + segment
Report an error
Correct Answer: A. Segment × 16 + offset
Explanation: A segment value is shifted left by four bits, equivalent to multiplying by 16, and the offset is then added.
Reference: Standard microprocessors and microcontrollers: 8086 segmentation
Question 2
Microprocessors & Microcontrollers8086 Segmentation

For 8086 address 1234H:0010H, the physical address is?

  • A12340H
  • B12350H
  • C12440H
  • D01244H
Report an error
Correct Answer: B. 12350H
Explanation: 1234H×10H=12340H; adding 0010H gives 12350H.
Reference: Standard microprocessors and microcontrollers: 8086 segmentation
Question 3
Microprocessors & Microcontrollers8086 Segmentation

For 8086 address 2000H:1234H, the physical address is?

  • A21234H
  • B32340H
  • C201234H
  • D03234H
Report an error
Correct Answer: A. 21234H
Explanation: 2000H×10H=20000H; adding 1234H gives 21234H.
Reference: Standard microprocessors and microcontrollers: 8086 segmentation
Question 4
Microprocessors & Microcontrollers8086 Segmentation

The maximum size of one logical 8086 segment is?

  • A16 KB
  • B32 KB
  • C64 KB
  • D1 MB
Report an error
Correct Answer: C. 64 KB
Explanation: The 16-bit offset can range from 0000H to FFFFH, so a segment can span up to 64 KiB.
Reference: Standard microprocessors and microcontrollers: 8086 segmentation