MCQ Practice Question
For a register-to-register synchronous path, Tcq=2 ns, maximum combinational delay=11 ns, setup time=2 ns, and worst-case clock uncertainty=1 ns. What minimum clock period is required using Tclk ≥ Tcq + Tcomb + Tsetup + Tuncertainty?
Correct Answer: C. 16 ns
Explanation: Substituting the values gives Tclk ≥ 2+11+2+1 = 16 ns.
Reference: Standard digital electronics: maximum clock frequency timing
