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MCQ Practice Question

Electronic Devices & Circuits Operational Amplifiers

An op-amp has a gain-bandwidth product of 1 MHz. For a closed-loop noise gain of 100 in a single-pole approximation, the expected bandwidth is approximately?

A1 kHz
B10 kHz
C100 kHz
D1 MHz

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Correct Answer: B. 10 kHz

Explanation: For a single-pole compensated op-amp, closed-loop bandwidth is approximately GBW divided by noise gain: 1 MHz/100 = 10 kHz.

Reference: Standard analog electronics: gain-bandwidth product

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