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MCQ Practice Question

Electronic Devices & Circuits Operational Amplifiers

An op-amp has a slew rate of 0.5 V/microsecond. Approximately what minimum time is required for its output to change by 10 V at the maximum slew rate?

A0.05 microsecond
B5 microseconds
C20 microseconds
D50 microseconds

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Correct Answer: C. 20 microseconds

Explanation: Time = voltage change / slew rate = 10 V / (0.5 V/microsecond) = 20 microseconds.

Reference: Standard analog electronics: slew-rate calculation

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