An op-amp has a slew rate of 2 V/microsecond. The minimum time for a 10 V output change at this limit is?

  • A2 microseconds
  • B5 microseconds
  • C10 microseconds
  • D20 microseconds
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Correct Answer: B. 5 microseconds
Explanation: Time = delta V/SR = 10/2 = 5 microseconds.
Reference: Standard analog electronics: operational amplifiers
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